Getting good at LeetCode Java can feel like a puzzle sometimes, right? You see all these problems, and you’re not sure where ...
count = 0 # lets say count == 3, it means until this idx, if 0 appeared x time, 1 appeared x+3 time res = 0 # So, once count == 3 appears at the other position again, for i in range(len(nums)): # ...
一部の結果でアクセス不可の可能性があるため、非表示になっています。
アクセス不可の結果を表示する